City of Lake Alfred
Lake Alfred is a city in Polk County, Florida, United States. The population was 3,890 at the 2000 census. As of 2004, the population recorded by the U.S. Census Bureau is 3,944.
Area
- Total
- 8.6 sq mi (22.2 km²)
- Land
- 4.9 sq mi (12.7 km²)
- Water
- 3.7 sq mi (9.5 km²)
Elevation
- 174 ft (53 m)
Population (2000)
- Total
- 3,890
- Density
- 452.3/sq mi (175.2/km²)
ZIP Code
- 33850
Area Code
- 863
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